h=1x-x^2/40

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Solution for h=1x-x^2/40 equation: 


x in (-oo:+oo)

h = 1*x-((x^2)/40) // - 1*x-((x^2)/40)

h+(x^2)/40-(1*x) = 0

h+(x^2)/40-x = 0

h+1/40*x^2-x = 0

DELTA = (-1)^2-(1/40*4*h)

DELTA = 1-1/10*h

1-1/10*h = 0

1-1/10*h = 0 // - 1

-1/10*h = -1 // : -1/10

h = -1/(-1/10)

h = 10

DELTA = 0  <=>  t_1 = 10

x = 1/(1/40*2) i h = 10

x = 20 i h = 10

( x = ((1-1/10*h)^(1/2)+1)/(1/40*2) or x = (1-(1-1/10*h)^(1/2))/(1/40*2) ) i h > 10

( x = 20*((1-1/10*h)^(1/2)+1) or x = 20*(1-(1-1/10*h)^(1/2)) ) i h > 10

h-10 > 0

h-10 > 0 // + 10

h > 10

x in { 20, 20*((1-1/10*h)^(1/2)+1), 20*(1-(1-1/10*h)^(1/2)) }

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